I don’t usually think deep in making programs. Mostly, I just follow the basics and find the commands and compile it to make the program.
- Google the Create the MYSQL command function to connect to the database
http://www.w3schools.com/php/php_mysql_connect.asp
<?php $servername = "localhost"; $username = "username"; $password = "password"; // Create connection $conn = new mysqli($servername, $username, $password); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } echo "Connected successfully"; ?>
2. Google the upload command function and compile it with the mysql connect function
http://www.w3schools.com/php/php_file_upload.asp
<?php $servername = "localhost"; $username = "username"; $password = "password"; // Create connection $conn = new mysqli($servername, $username, $password); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } echo "Connected successfully"; $target_dir = "uploads/"; $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); $uploadOk = 1; $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION); // Check if image file is a actual image or fake image if(isset($_POST["submit"])) { $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]); if($check !== false) { echo "File is an image - " . $check["mime"] . "."; $uploadOk = 1; } else { echo "File is not an image."; $uploadOk = 0; } } ?> <!DOCTYPE html> <html> <body> <form action="upload.php" method="post" enctype="multipart/form-data"> Select image to upload: <input type="file" name="fileToUpload" id="fileToUpload"> <input type="submit" value="Upload Image" name="submit"> </form> </body> </html>
From that we created a simple mysql connect with php file upload.